Pls help me! -2x^2(x+3)(2x-5)

Question

Hi guys, please help me understand how does the distributive law applies to this problem, -2x^2(x+3)(2x-5). I distribute -2x^2 to each term in the brackets, but each time i'm getting the wrong solution! I must be doing something wrong and i can't figure what. Please help me with explanation, or eventually advice what method to use in solving this. Thank you in advance

Answer 1

The first thing to do is to apply the distributive law to the bracketed expressions:

x(2x-5)+3(2x-5)=2x^2-5x+6x-15=2x^2+x-15.

Now apply -2x^2 to this quadratic expression: -4x^4-2x^3+30x^2.

Answer 2

-2x^2(x+3)(2x-5)

SOL: Keep the equation which is already outside the bracket outside the bracket(keep at same place.)

-2x^2 (x)(2x-5) +3(2x-5)

Multiply all the numbers/variables of any one bracket to the other bracket one by one..

-2x^2  (2x^2-5x) (+6x-15)..

Then simplify this and get correct answer...     Thanks allot..

Comments

Thank you