So I'm trying to get the opposite of a formula but I can't figure it out. The formula is y=x*(x-1)*500
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y=x(x-1)*500=500x^2-500x. The inverse of this formula has to have the form x=....

But this is a quadratic in x: 500x^2-500x-y=0.

It can also be written x^2-x=y/500.

Complete the square on the left-hand side: x^2-x+1/4=y/500+1/4, and because we had to add 1/4 to complete the square on the left, we must add the same value to the right.

(x-1/2)^2=y/500+1/4; x-1/2=±√(y/500+1/4), so x=1/2±√(y/500+1/4) gives us to solutions for x, one for the positive root and one for the negative.

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