How many even numbers of three different digits can be formed by choosing from the digit

Question

2,3,4,5,6,7,8,9

Answer 1

The even numbers must end with 2, 4, 6 or 8.

Start with those ending in 2: there are 7 remaining digits from which pairs of digits must be selected. There are 7*6=42 permutations. The same applies to those ending in 4, 6 or 8. So the total is 4*42=168.

Comments

Thanks