Make T the subject of the formula L=3 √m²-T²÷Px hence evaluate T when M=10,P=6,x=⅔ and L=3

Make T the subject formula
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L=3√(m^2-T^2)/Px

PxL/3=√(m^2-T^2)

Square both sides: (PxL/3)^2=m^2-T^2

T^2=m^2-(PxL/3)^2, T=±√(m^2-(PxL/3)^2)=±(1/3)√(9m^2-(PxL)^2).

PxL=6*(2/3)*3=12.

T=±(1/3)√(900-144)=±(1/3)√756=2√21=±9.1652 approx.
by Top Rated User (1.2m points)

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