I’m not sure what your symbols mean, so I’ll explain my assumptions first.
p→q: I take this to mean “p implies q”. That is, if p=1 (p is TRUE) then q=1 (TRUE). So I take (p→q) to mean that if p=0 then q must be zero, so if it isn’t the result is FALSE (0). This would give the truth table:
p q (p→q)
0 0 1
0 1 0
1 0 0
1 1 1
r⟷s: I take this to mean that r and s are equivalent, so where r and s are the same, (r⟷s)=1 and where they are different, (r⟷s)=0, which seems to be the same as (p→q).
A different interpretation of (p→q) could be that, whatever q is, (p→q)=p giving us the truth table:
p q (p→q)
0 0 0
0 1 0
1 0 1
1 1 1
The third operator ⨁ I understand to be exclusive-OR, and the truth table is:
0⨁0=0,
0⨁1=1,
1⨁0=1,
1⨁1=0.
I hope this info helps you.
Example:
p q (p→q) r s (r⟷s) (p→q)⨁(r⟷s)
1 1 1 1 0 0 1
0 1 0 1 1 1 1
This is just two rows out of the 16 rows making up the truth table. The remaining 14 rows depend on what → and ⟷mean as binary operators.