Solve for x, 2[x+2/2x-3]-9[2x-3/x+2]=3, x is not equal to -2 and 3/2

Question

Plzz try to answer by today.....i have maths examzz tmrw.....its urgent....plzzzzz

Answer 1

Solve for x, 2[x+2/2x-3]-9[2x-3/x+2]=3, x is not equal to -2 and 3/2

I assume the equation should be,

2[(x + 2)/(2x - 3)] - 9[(2x-3)/(x + 2)] = 3         multiply both sides by (2x - 3)(x + 2)

2(x + 2)^2 - 9(2x-3)^2 = 3(2x - 3)(x + 2)       expanding the brackets

2x^2 + 8x + 8 - 36x^2 + 108x - 81 = 6x^2 + 3x - 18

40x^2 - 113x + 55 = 0

(8x - 5)(5x - 11) = 0

Answer: x = 5/8, x = 11/5