Please how will you solve X^4 + 35X^2 - 36 = 0. Thanks and God bless you! Amen.

Question

its a linear equation. just like the one I posted prevoulsly.

Answer 1

(X^2-1)(X^2+36)=0=(X-1)(X+1)(X^2+36), so the real solution is X=1, X=-1.

The complex solution gives us additionally X=6i and X=-6i (imaginary numbers).