I need asnwer for this question       Iff(x)=a,thenF(x)=ax+C
Iff(x)=xa,thenF(x)=xa+1a+1+C(unlessa=1)
Iff(x)=1x,thenF(x)=ln(x)+C
Iff(x)=ex,thenF(x)=ex+C
Iff(x)=cos(x),thenF(x)=sin(x)+C

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