Under trigonometric detivatives in calculus
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By Multiplying by form of 1, evaluate 1/(cscx-cotx) dx

1/(cscx - cotx) =

1/(1/sinx - cosx/sinx) =

1/(1/sinx - cosx/sinx)*(sinx/sinx) =

sinx/(1 - cosx)

And int sinx/(1 - cosx) dx = ln(cosx - 1)

by Level 11 User (81.5k points)

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