Under trigonometric detivatives in calculus
asked Nov 24, 2016 in Calculus Answers by Martin Kishao
reshown Nov 25, 2016 by Rod

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1 Answer

By Multiplying by form of 1, evaluate 1/(cscx-cotx) dx

1/(cscx - cotx) =

1/(1/sinx - cosx/sinx) =

1/(1/sinx - cosx/sinx)*(sinx/sinx) =

sinx/(1 - cosx)

And int sinx/(1 - cosx) dx = ln(cosx - 1)

answered Nov 24, 2016 by Fermat Level 11 User (76,040 points)
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