Its under trigonometric functions in calculus under derivatives
asked Nov 23, 2016 in Calculus Answers by Martin Kishao

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1/(cosec(x)-cot(x))dx=sin(x)dx/(1-cos(x)), by multiplying top and bottom by sin(x).


Let y=1-cos(x) so y'=sin(x) and dy=sin(x)dx so to evaluate ∫(sin(x)/(1-cos(x))dx we can replace sin(x)dx with dy and we have ∫dy/y=ln|y|=ln|1-cos(x)| or more generally ln|A(1-cos(x)| where A is a constant.


answered Nov 25, 2016 by Rod Top Rated User (486,780 points)
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