The side of a square is 3x^4y^2z cm. The side of the smaller square is 8a cm. How big is the first square than the second square. Express the difference in terms of x,y,z and in factored form.

Question

It's our math assignment please help me

Answer 1

The area of the first square is (3x^4y^2z)^2 and the area of the second square is (8a)^2, both measured in square centimetres. The difference in areas is (3x^4y^2z-8a)(3x^4y^2z+8a) in factored form.