1/6 of 9x -5000

Question

A house costs 9 times more than the lot. The lots costs 1/6 of the house price minus 5000.

Answer 1

Two interpretations:

(1) Price of lot is L, price of house is H. H=9L is assumed to mean 9 times more than (as much as) the lot.

L=H/6-5000.

Substitute for H: L=9L/6-5000=3L/2-5000.

3L/2-L=5000.

L/2=5000 so L=10000 and H=9L=90000.

(2) Price of lot is L, price of house is H. H=9L+L=10L, is assumed to mean 9 times more than the lot.

L=H/6-5000.

Substitute for H: L=10L/6-5000=5L/3-5000.

5L/3-L=5000.

2L/3=5000 so L=3*5000/2=7500 and H=10L=75000.