x+y=5000 and .08x+.02y=232 what is y?

Suppose you invest $5,000 in stocks and bonds paying 8% and 2%, respectively. The interest from both investments after one year is $232. For the following problems, use x for the amount invested in stocks and y for the amount invested in bonds

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1 Answer

x + y = 5000

y = 5000 - x

0.08x + 0.02y = 232

0.08x + 0.02(5000 - x) = 232

0.08x + 100 - 0.02x = 232

0.06x + 100 = 232

0.06x = 132

6x = 13200

x = 2200

x + y = 5000

2200 + y = 5000

y = 2800

$2,800.

by Level 13 User (103k points)

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