(tan(X)+tan(Y))÷(1-tan(X)tan(Y))=(cot(X)+cot(Y))÷(cot(X)cot(Y)-1) Proof steps please?

Uhh...it's a trigonometric identity proof.
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1 Answer

 

Divide denominator and numerator by tan(X):

(1+tan(Y)cot(X))/(cot(X)-tan(Y)).

Now divide both by tan(Y):

(cot(Y)+cot(X))/(cot(X)cot(Y)-1)=(cot(X)+cot(Y))/(cot(X)cot(Y)-1).

by Top Rated User (1.2m points)

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