Find the fractional side lengths of a rectangle that has a perimeter of 64 5/6 inches. Then find the area of the rectangle

Question

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Comments

Insufficient information. There are an infinite number of rectangles with this perimeter which is equal to twice the sum of length and width. Also need area or relative lengths of sides.

Answer 1

Perimeter is 2(L+W) where L=length W=width.

2(L+W)=64 5/6"=389/6".

L+W=389/12. L=389/12-W, so the relationship can be plotted on a straight line graph.

389/12-W>0 so W<389/12", or W,L<32 5/12".

If W=L the rectangle is a square so L=W=16 5/24". 16 5/24≤{L W}<32 5/12.

Area is variable=LW=L(389/12-L)=389L/12-L^2 which is maximum when L=W=389/24 (area=262.71 sq in approx.)

Answer 2

As we know perimeter = 2(length+width)

2(length+width)=64 5/6

Length+width=389/12

Length = 389/12-width

So,
width and length are grater than 389/12

Finding Aera of Rectangle

Answer 3

129 4/6 inches