asked Apr 28, 2016 in Word Problem Answers by anonymous

Insufficient information. There are an infinite number of rectangles with this perimeter which is equal to twice the sum of length and width. Also need area or relative lengths of sides.

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2 Answers

Perimeter is 2(L+W) where L=length W=width.

2(L+W)=64 5/6"=389/6".

L+W=389/12. L=389/12-W, so the relationship can be plotted on a straight line graph.

389/12-W>0 so W<389/12", or W,L<32 5/12".

If W=L the rectangle is a square so L=W=16 5/24". 16 5/24≤{L W}<32 5/12.

Area is variable=LW=L(389/12-L)=389L/12-L^2 which is maximum when L=W=389/24 (area=262.71 sq in approx.)
answered Apr 29, 2016 by Rod Top Rated User (582,400 points)

As we know perimeter = 2(length+width)

2(length+width)=64 5/6


Length = 389/12-width

width and length are grater than 389/12

Finding Aera of Rectangle

answered May 5, 2016 by John Marsh Level 8 User (30,400 points)

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