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2(L+W)=64 5/6"=389/6".

L+W=389/12. L=389/12-W, so the relationship can be plotted on a straight line graph.

389/12-W>0 so W<389/12", or W,L<32 5/12".

If W=L the rectangle is a square so L=W=16 5/24". 16 5/24≤{L W}<32 5/12.

Area is variable=LW=L(389/12-L)=389L/12-L^2 which is maximum when L=W=389/24 (area=262.71 sq in approx.)

2(length+width)=64 5/6

Length+width=389/12

Length = 389/12-width

So,

width and length are grater than 389/12

Finding **Aera of Rectangle**

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