I want to know how to solve this.
asked Apr 15, 2016 in Other Math Topics by anonymous

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2 Answers

2^x+2^y=8

take log tu base 2...x+y=log2(8)=3

then 3^x+3^y=18..take log tu base 3 & yu get x+6=loe3(18)

=2.630929753571457

but sumthun rong, kauz yu now hav x+k6=2.630929753571457
answered Apr 15, 2016 by muneepenee

2^x+2^y=8=2^3; 3^x+3^y=2*3^2.

The second equation seems to hold the clue because there are two terms on the left and if they are equal we have 2*3^x=2*3^2, and x=2 so y=2. Now we turn to the first equation: 2*2^x=2*2^2, so x=y=2; therefore the solution is x=y=2.

 

answered Apr 16, 2016 by Rod Top Rated User (479,700 points)

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