ab + 3a - 6b -18 over b^2 - 9 write rational expression in lowest terms

ab + 3a - 6b - 18

b^2 - 9                 =  (b  + 3)(b + 3)

 

I can't figure out the top expression?

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2 Answers

Rewrite: b(a-6)+3(a-6)=(b+3)(a-6); divisor: (b-3)(b+3)

Provided b is not -3, we can cancel out the common factor b+3: (a-6)/(b-3).
by Top Rated User (1.2m points)
b^2-9=(b-3)*(b+3)

top be a*(b+3) -6(b-3)

so yu get [a(b+3)/(b-3)] -[6/(b+3)]
by

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