determine the following integrals: [xe^3 + pie^e - 3/x + x/3] dx

Note it is often necessary to simplify the integrand first
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Interal = I = I (xe^3 + pie^3 -3/x+x/3)dx =

e^3*x^2/2 - 3lnx + x^2/6 + C

e^3 = c,   I Cdx  = 0

pie^3 = c  . I cdx = 0

Ixdx = x^2/2

dx/x = lnx

 

 

 

 

 

by Level 8 User (36.8k points)
edited by

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