Question

How did Integrating 1- 9/(14v-44) was v- 9/14 (log 14v +44 ) shouldn't it be 9 log (14v+44)?

Answer 1

No, the answer is correct, because the 14 comes from differentiating the expression 14v+44. You can see this if you put p=14v+44; dp/dv=14; dv=dp/14; integral of (9dv/(14v+44))=integral of (9dp/(14p))=(9/14)log(14v+44).

Answer 2

Differential equations of the first order and first degree. Any differential equation of the first order and first degree can be written in the form

 

 

Example. The differential equation

 

             

 

can also be written as

 

            (x - 3y)dx + (x - 2y)dy = 0