solve for the angle theta, between 0 an 2pi

sin² theta = cos² theta
asked Aug 29, 2015 in Trigonometry Answers by anonymous

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Divide both sides by cos^2(theta): tan^2(theta)=1, so tan(theta)=+1. Theta=(pi)/4 (45 degrees), 3(pi)/4 (135°), 5(pi)/4 (225°), 7(pi)/4 (315°). These values are in consecutive quadrants where the tangent alternates between plus and minus 1. (QI, QIII are +1; QII, QIV are -1).

answered Aug 29, 2015 by Rod Top Rated User (592,720 points)

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