Find all soloutions to the equation on the interval [0,4pi] : sin (2theta)= 3cos(theta)
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sin(2ø)=2sinøcosø, so 2sinøcosø=3cosø, and cosø(2sinø-3)=0. Solutions are ø=(pi)/2, 3(pi)/2, 5(pi)/2, 7(pi)/2 because cosø=0 for these values. sinø=3/2 has no solutions, because sin cannot exceed 1.

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