2-logx=log5

Solve for x
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2 Answers

logx=2-log5. Assume log to base 10: logx=log100-log5=log(100/5)=log20 so x=20.

Assume log to base b: logx=log(b^2)-log5=log(b^2/5) so x=b^2/5.

If b=2, for example, x=4/5.
by Top Rated User (1.2m points)
2-logx = log5

logx + log5 = 2

log(5x) = 2

10^2 = 5x

100= 5x

x = 100/5

x = 20
by Level 8 User (36.8k points)

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