evaluate y' at the point (-1,0). 6x^3y-2x^2=2

~~evaluate y' at the point (-1,0).
6 x^3 y - 2 x^2 = 2
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1 Answer

Differentiate with respect to x: 18x^2y+6x^3y'-4x=0. Put y=0 and x=-1: -6y'+4=0, so 6y'=4 and y'=2/3.

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