Solve the system of equations to 4 decimal places:

x=ln(y+1.5)

y=1.5+ln(x)
in Algebra 2 Answers by Top Rated User (1.2m points)

Hint:

Substitute for y in the first equation:

x=ln(3+ln(x)), an equation involving only one variable. The log of a number is always smaller than the number itself so this fact can be used to generate an iterative process. Start with x=1; the next value for x becomes ln(3)=1.1 approx; the next value of x is ln(3+ln(1.1))=1.13; the next value is ln(3+ln(1.13))=1.14; the next 1.141 and so on. With each iteration the result converges fairly rapidly to a stable approximation to 4 decimal places. At that point y can be found from the second equation. Using a calculator more accuracy is obtained than the figures given above as examples, and a solution is forthcoming when the accuracy of the calculator is reached so that no new values are generated (1.141890548916, for example, y=1.632685265061).

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1 Answer

Best answer

Given x=ln(y+1.5)
y=1.5+ln(x)

Substitute (1)in equation (2)
x =0.161206
y = -0.325072

Understand more about System of Equations

 

by Level 8 User (30.1k points)
selected by
Thanks, John. It looks like you found the other solution (there are two). Congratulations!

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