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Question

1.Find the altitude of an isosceles triangle whose vertex angle is 38 degrees and whose equal sides are 7.9m long.

Answer 1

Bisect the apex angle to form two back-to-back congruent right-angled triangles. Take one triangle. The hypotenuse is 7.9m and the apex angle is bisected at 19 degrees. The altitude of the isosceles triangle is the common side of the right-angled triangles=7.9cos19 (cos19=adjacent side divided by hypotenuse=altitude/7.9)=7.47m approx.

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