solve for b 3b(b-4)-6(4-B)

solve for b  3b(b-4)-6(4-B)
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If you mean 3b(b-4)=-6(4-b), then 3b(b-4)=6(b-4), 3b=6, b=2 or 4 (because b=4 causes both sides of the equation to become zero).

If you mean 3b(b-4)-6(4-b)=0, then 3b(b-4)=6(4-b)=-6(b-4), 3b=-6, b=-2 or 4.

by Top Rated User (1.2m points)

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