There is a 75 percent probablitly that an individual pea will have green pod.  What is the probability that among the nine, no more than 1 has a green pod.  Is it unusual to get more than one pea with a green pod.  Why or why not.
in Statistics Answers by Level 1 User (420 points)

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

The probability of one pea having a green pod is 0.75 and therefore the probability of the pea not having a green pod is 1-0.75=0.25. The probability of none of the 9 having a green pod is 0.25^9=0.0000038. The probability of just one having a green pod is 9*0.25^8*0.75=0.000103, that is, 8 without a green pod and one with. There are 9 ways this can happen because the pea with the pod can be any one of the nine peas. Add these two probabilities together: 0.0001068 approx. So this is a small probability which means that it's not likely that we would get at most one pea with a pod. Therefore it is highly likely that in 9 peas more than 1 would contain a pod. It would be unusual to get at most one pea with a pod, and it would be usual to get more peas with a pod.

by Top Rated User (1.2m points)

Related questions

1 answer
asked Oct 15, 2017 in Statistics Answers by simone | 441 views
1 answer
asked Sep 15, 2016 in Statistics Answers by math93 Level 2 User (1.7k points) | 1.2k views
1 answer
1 answer
1 answer
asked Nov 27, 2017 in Other Math Topics by kate98 Level 1 User (200 points) | 400 views
1 answer
asked Jan 20, 2015 in Other Math Topics by zul | 691 views
1 answer
1 answer
asked Oct 22, 2013 in Other Math Topics by anonymous | 732 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
731,436 users