what is the discriminant of 2n^2-4n+2=0

Question

State the number with the soultions to get the answer you need

Answer 1

2n^2 - 4n + 2 = 0
Identify a,b,c for the problem:
In this case a=2,b=-4,c=2

2nd: Evaluate b^2-4ac
In this case you get (-4)^2-4(2)(2) =16-16=0

3rd: If the value is > there are two real unequal roots
If the value is 0 there are two real equal roots
If the value is <0 there are two uneqal complex roots

Hence the value is 0 there are two real equal roots

Pre Algebra Math Help

Answer 2

The discriminant is (-4)^2-4*2*2=0 (solution to the quadratic is (-b+sqrt(D))/2a where the quadratic is represented by ax^2+bx+c=0 and D is the discriminant b^2-4ac.) This means there is only one solution because +0=0. The answer is n=4/4=1. The original equation is in fact 2(n-1)^2= so (n-1)^2=0 and n=1 is the only solution.