im am trying to find the answer to this problem
in Geometry Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

The question doesn’t state where F is in relation to A, B or E, so we have to guess. Here are two guesses.

 

If ABF is a straight line then ABE+EBF=180, so 2n+7+4n-13=180, 6n-6=180.

Divide each side by 6: n-1=30 so n=31 and mABE=2n+7=2×31+7=62+7=69°.

 

If BF bisects ABE, then ABE=2×EBF, so 2n+7=2(4n-13)=8n-26. So 6n=33 and, dividing both sides by 3: 2n=11. Therefore mABE=2n+7=11+7=18°.

by Top Rated User (762k points)

Related questions

1 answer
asked Sep 13, 2019 in Geometry Answers by anonymous | 155 views
0 answers
0 answers
1 answer
1 answer
asked Sep 23, 2012 in Geometry Answers by anonymous | 1.3k views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
85,064 questions
90,192 answers
2,057 comments
57,077 users