The equation is graphically represented by a line of negative slope (\) passing through (0,6) and (12,0) since 6 and 12 are the y and x intercepts respectively. The point (-4,2) lies below the line, since, when x=-4, y=8 and when y=2, x=8. The points (-4,2), (-4,8) and (8,2) form a right-angled triangle, with hypotenuse length 6sqrt(5). The perpendicular from (-4,2) forms part of the line y=x/2+b, where b is the y intercept. The slope of this line is the positive version of the other line, i.e., 1/2. To find b, put in x=-4 when y=2: b=4. So the equation of the line is y=x/2+4, meeting y=-x/2+6 at y=5, x=2 (2,5). The question doesn't specify what is required so I've supplied as much info as I can guess at!