what is the solution to the system
(x-y+2z=7) (2x+y+z=8) (x=5)
1) x - y + 2z = 7
2) 2x + y + z = 8
3) x = 5
1) x - y + 2z = 7
5 - y + 2z = 7
-y + 2z = 7 - 5
-y + 2z = 2
2) 2x + y + z = 8
2(5) + y + z = 8
10 + y + z = 8
y + z = 8 - 10
y + z = -2
-y + 2z = 2
+(y + z = -2)
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3z = 0
3z = 0
z = 0
1) x - y + 2z = 7
5 - y + 2(0) = 7
5 - y + 0 = 7
-y = 7 - 5
-y = 2
y = -2
2) 2x + y + z = 8
2(5) + y + 0 = 8
10 + y = 8
y = 8 - 10
y = -2
Answer: x = 5, y = -2, z = 0