find the vertices of the hyperbola

Question

 

x^2/49 - y^2/16=1

 

 

 

Answer 1

Was it like this:
(x^2)/49 - (y^2)/16=1
Or this:
x^2/49 - y^2/16=1
(Was it x squared divided by 16 or was it x to the power of 2 divided by 16)
If you can clarify for me I should be able to help :)