Solving system of equation by linear combinations of

2+4y=8

-5x+4y=1?
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1 Answer

I think the first equation should be 2x+4y=8.

So we have 2x+4y=8 and -5x+4y=1.

We can combine these as (2x+4y)-(-5x+4y)=8-1,

2x+5x=7, 7x=7, so x=1, substitute x=1 in either equation:

2+4y=8 or -5+4y=1, 4y=6, y=1½ or 3/2.

 

by Top Rated User (660k points)

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