equation of a logarithm?

find the equation of x, log[base5] (x+1)2 = log[base5] (x2-3)
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The logs are to the same base, so we can equate the log arguments: (x+1)^2=x^2-3. x^2+2x+1=x^2-3, so 2x+1=-3 and 2x=-4 so x=-2. Check: log((-2+1)^2)=log(1)=0; log(4-3)=log(1)=0, so both sides are zero.

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