xy^3dx + (y+1)e^-xdy=0

help me to solve this equation..thanks
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Given xy^3dx + (y+1)e^-xdy=0
xy^3 dx = -(y+1)/e^x dy
xe^x dx =-(y+1)/y^3 dy
xe^x - e^x + c1= -[ (1/y^2) + 1/y^3 ]
xe^x - e^x + c1 = -[-y^-1 + -(1/2y^2)] + c2
xe^x - e^x +c1 = y^-1 + 1/2y^2 + c2 ; c2-c1 = C
e^x(x-1) = 1/y + 1/(2y^2) + C
 

by Level 8 User (30.1k points)
edited by

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