quadratik be equashun in form y=ax^2+bx+c
Zampel...sumthun fall kauz av GRAVITY hav foers=g*mass downward which giv
vertikal speed=g*time
Integrate that & yu get vertial distans=(1/2)gt^2+start-speed * t
yuze quadratik equashun tu find zeroes av quadratik equashun
roots=-b/2a +-sqrt(b^2-4ac)/2a
root=value av x that giv y=0