I need my word problem solved now and I need to know how to do it for the future

Question

A university bookstore recently sold a wirebound graph-paper notebook for $0.88, and a college-ruled notebook for $2.38. At the start of spring semester, a combination of 50 of these notebooks were sold for a total of $59.00. How many of each type were sold? PLEASE HELP ME.

Answer 1

its a simultaneous equation

A university bookstore recently sold a wirebound graph-paper notebook for $0.88, and a college-ruled notebook for $2.38. At the start of spring semester, a combination of 50 of these notebooks were sold for a total of $59.00. How many of each type were sold? PLEASE HELP ME.

 

let X = number of college ruled notebooks

let Y = number of graph paper notebooks

 

we know we sold 50 in total so that means

X + Y = 50

we know the price of each  2.38 for the college and 0.88 for the graph paper

2.38*X + 0.88*Y = 59.00

 

now we can use either elimination method or matrix math .. its simpler with these types for elimination

X = 50 - Y

then substitute this into the second equation and solve for Y

2.38*X + 0.88*Y = 59.00

2.38*(50 - Y) + 0.88*Y = 59.00

119 - 2.38Y + 0.88Y = 59.00

Y(-2.38 + 0.88) = 59.00 - 119

Y  = -60/-1.5

Y = 40

we can use either of the equations to find x now but the first is easier

X = 50 - Y

X = 50 - 40

X = 10

 

so you have 40 graph paper books and 10 ruled books

to check see if the amounts come to 59 in the second equation

2.38*10 = 23.8

40*.88 =  35.2

23.8 + 35.2 = 59.00

so its confirmed the answer is  correct

 

 

 

 

 

Answer 2

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Answer 3

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Answer 4

A researcher known from past studies that the standard deviation of the times it takes inspect a car is 16.2 minutes. A sample of 23 cars is selected and inspected. The standard deviation was 11.5 minutes. At a=0.05, can it be concluded that the standard deviation has changed? Use the P -value method.

yes                           no

Answer 5

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