EO = 2x – 20 and OC = 70 – x. Solve for x.

EO = 2x – 20 and OC = 70 – x. 
Solve for x.

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2 Answers

Since OB bisects EC where they intersect, at point O, 
the two lengths EO and OC must be equal. 

2x - 20 = 70 - x 
3x = 90 [adding x+20 to each side] 
x = 30 [dividing each side by 3 to obtain answer D]

by Level 10 User (57.4k points)
If EOC is an isosceles triangle and EO=OC, 2x-20=70-x, 3x=90, so x=30.
by Top Rated User (1.2m points)

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