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answer to ln (e/ex)

assuming that ex means e^x, then

e/ex means e/(e^x) = e*e^(-x) = e^(1-x)

Therefeore,

ln(e/ex) means ln(e/(e^x)) = ln(e^(1-x)) = (1-x).ln(e) = (1-x).1 = 1 - x

Answer: 1 - x

by Level 11 User (81.5k points)
...or ln(e)-ln(e^x)=1-x.
... that's a bit faster! :)

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