please find the derivative of y=x.e^x.lnx
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y = x * e^x * ln(x)

y ' = (1) * e^x * ln(x) + x * (e^x) * ln(x) + x * e^x * (1/x)

y ' = e^x * ln(x) + x * e^x * ln(x) + e^x

y ' = e^x * (ln(x) + x * ln(x) + 1)
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