Let x = divisor and y = dividend, then y/x=3 remainder 12. So 3x+12=y and thus we can relate x and y, and plot them on a graph as a straight line. I assume x and y are both positive. The remainder tells us that x must be greater than 12. Let x=13, then y=51. (After that, y increases by 3 when x increases by 1.) These are the smallest integer values for divisor and dividend. Let x=100, then y=312. These values fit, too. The graph y=3x+12 is a line passing through the intercepts at (0,12) and (-4,0), but the line actually starts at (13,51) if we want only positive integer values. Nevertheless, the line gives all possible values, negative as well as positive, and includes fractions.