(1/8)^(x - 2) =4^(2x - 4) lnx^a=alnx
ln((1/8^(x - 2)) = ln(( 4^(2x - 4)) ln1 = 0
(x - 2) ln(1/8) = 2(x - 2 )ln 4 ln1/8 = ln 1 - ln 8
(x - 2 )( ln 1 - ln 8) = 2( x - 2)ln 2^2
( x - 2 ) ( - ln 2^3) = 2*2( x - 2)ln2
-3( x - 2)ln2 - 4( x - 2)ln2 = 0
- 7 ln2(x - 2) = 0
x - 2 = 0
x = 2
(1/8)^( x - 2) =4^(2x - 2)
(1/8)^( 2 - 2) = 4^( 2*2 - 4)
(1/8)^0 =4^0
1= 1 a^0 = 1