Solve the system:

4/3j + 5/6k = 13

-1/j + 5/k = -3
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1 Answer

I read this as 4/(3j)+5/(6k)=13, -1/j+5/k=-3.

Let a=1/j and b=1/k then:

(4/3)a+(5/6)b=13, -a+5b=-3, so a=5b+3.

Substitute for a in the other equation:

(4/3)(5b+3)+(5/6)b=13, that is:



45b=54, b=54/45=6/5, so k=⅚.

a=5b+3=6+3=9, so j=1/9.


(4/3)9+(5/6)(6/5)=12+1=13 OK;

-9+6=-3 OK.

So solution is (j,k)=(1/9,⅚).

by Top Rated User (815k points)

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