85= x^2 / (0.05)^2 (0.05)

Question

This is the question I was asked: 

Given the following system in equilibrium: 2SO2(g) + O2(g) ⇌ 2SO3(g)

If Keq=85.0, [SO2]=0.0500 M and [O2]=0.0500M, what is the concentration of SO3 at equilibrium?

Set up, it looks like this: 85=        x^2        

                                           (0.05)^2 (0.05)

             

The correct answer (I guess) is 0.103; I don't know how they got that. Please show your work so as I may be able to figure out how you get the answer. Thanks :)

Answer 1

mi ges be that stuf shood be

x^2 / (0.05)^3=85

thus, x^2=(0.05)^3*85

=0.000125*85

x^2=0.010625

so x=sqrt(0.010625)

x=0.10307764