Simplify. Assume the divisor is not zero.
 (8x^2y^2 - 4xy) ÷ 4xy
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3 Answers

(8x^2y^2 - 4xy) ÷ 4xy

4xy(2xy - 1) / 4xy

2xy - 1

by Level 10 User (55.7k points)
2xy - 1

--------------------------------------------------   ; 2xy*4xy = 8x^2y^2

4xy | 8x^2y^2     -    4 xy   |

       8x^2y^2

      - 8x^2y^2

----------------------------------------        ; 4xy*( - 1) = -4xy

         0                - 4xy

                          - 4xy

                          + 4xy

 --------------------------------------

                              0

( 8x^2y^2 - 4xy ) /4xy = 2xy - 1
by Level 8 User (36.8k points)

Factor.

x2 – 7x + 12

by

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