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11 Answers

given two points (x1,y1) and (x2,y2) the distance is calculated by

sqrt((y2-y1)^2 + (x2-x1)^2)

in this case the two points are on the axes so it's simpler and can be calculated as

sqrt (7^2+7^2) = 7sqrt(2)
by Level 3 User (2.1k points)
An easy way to remember this is that x comes before y in the alphabet.... so the first variable is x and the second is y. The x-axis is vertical (_) and the y-axis is horizontal ( l ) so (0, -7)  is on the y-axis going down 7 and (-7,0) is on the x-axis going left 7. Hope this helps!
How do I draw the graph for this?
find the total length ofall the edges if you are given the base and height only : a surd equation
when (0,-7)
o is the x axis and -7 is the y axis
-7 in this cause is the x axis and 0 is on the y axis
mmm! =_="

find the distance between P(3,-1,2) and Q(-1,1,0)

show that the points p(3,-1,2) ,Q(4,1,4), R(6,0,4) are vertices of a right angled triangle
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