Express (1)/((x^3)+x) in partial fractions.
in Algebra 1 Answers by Level 1 User (200 points)

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1/(x^3+x)=(A/(x^2+1))+(B/x) in partial fractions.
So multiplying through by x(x^2+1) we get Ax+B(x^2+1)=1.
Put x=0 and we get B=1. Put x=1 and we get A+2B=1, so A=-1. This implies that:
(1/x)-(1/(x^2+1)) is equivalent to 1/(x^3+x), which is false.
The fallacy arises because x=0 can't be substituted in B/x, and because no matter what values for x are substituted, the equation containing A and B always equals 1.
For example, x=-1 gives -A+2B=1 while x=1 gives A+2B=1. This implies that A+2B=-A+2B, so A=0.
We must conclude then that the original expression is flawed or partial fractions cannot be applied.
by Top Rated User (663k points)

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