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       5x²+                17x+                  15.

So, A+C=5, C=5-A; -A+B+4C=17; -6A-3B+4C=15.

4C=17+A-B=15+6A+3B, 2=5A+4B, B=(2-5A)/4.

We now have B and C in terms of A, so substitute:



14=25A, A=14/25; C=5-A=111/25; B=(2-5A)/4=-1/5.

We can write these as decimals: A=0.56, B=-0.2, C=4.44.

Partial fractions:


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