what do natural logarithms have to do with area under a curve?
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2 Answers

integral(1/x)=ln(x)

from 1 tu e...ln(1)=0, ln(e)=1

integral=1-0=1
by

1/x dx .........[1,e]

∫1/x = ln x..........[1,e]

={lne} - {ln1} 

=1 -0

=1

by Level 3 User (4.0k points)

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